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仿射变换与透视变换
阅读量:2383 次
发布时间:2019-05-10

本文共 2701 字,大约阅读时间需要 9 分钟。

仿射变换保证物体形状的“平直性”和“平行性”。透视变换不能保证物体形状的“平行性”。仿射变换是透视变换的特殊形式。

将透视变换写成3*3矩阵形式,即为M;

以下面这张图为例,实现仿射变换,包括旋转,平移,缩放,剪切,以图像中心为变换中心;

仿射变换

旋转(逆时针旋转30度)

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Mat M=Mat::eye(3,3, CV_32FC1);

float alpha=PI/6;
float tx=0;
float ty=0;
float scale=1;

M.at<float>(0, 0) = cos(alpha);

M.at<float>(0, 1) = sin(alpha);
M.at<float>(0, 2) = (1-cos(alpha))*center.x - sin(alpha)* center.y;
M.at<float>(1, 0) = -sin(alpha);
M.at<float>(1, 1) = cos(alpha);
M.at<float>(1, 2) = sin(alpha)* center.x +(1-cos(alpha))*center.y;
M.at<float>(2, 0) = 0;
M.at<float>(2, 1) = 0;
M.at<float>(2, 2) = 1;

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平移(水平和垂直方向各向右平移20个像素)

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Mat M=Mat::eye(3,3, CV_32FC1);    float alpha=0;    float tx=20;    float ty=20;    float scale=0;    M.at
(0, 0) = cos(alpha); M.at
(0, 1) = sin(alpha); M.at
(0, 2) = (1-cos(alpha))*center.x - sin(alpha)* center.y + tx; M.at
(1, 0) = -sin(alpha); M.at
(1, 1) = cos(alpha); M.at
(1, 2) = sin(alpha)* center.x +(1-cos(alpha))*center.y + ty; M.at
(2, 0) = 0; M.at
(2, 1) = 0; M.at
(2, 2) = 1;

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缩放(图像缩小1/2)

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Mat M=Mat::eye(3,3, CV_32FC1);    float alpha=0;    float tx=0;    float ty=0;    float scale=0.5;    M.at
(0, 0) = cos(alpha) * scale; M.at
(0, 1) = sin(alpha) * scale; M.at
(0, 2) = (1-cos(alpha)* scale)*center.x - sin(alpha)* center.y* scale + tx; M.at
(1, 0) = -sin(alpha) * scale; M.at
(1, 1) = cos(alpha)* scale; M.at
(1, 2) = sin(alpha)* center.x* scale +(1-cos(alpha)* scale)*center.y + ty; M.at
(2, 0) = 0; M.at
(2, 1) = 0; M.at
(2, 2) = 1;

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错切变换(剪切变换):

 

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Mat M=Mat::eye(3,3, CV_32FC1);    float alpha=PI/12;    float tx=0;    float ty=0;    float scale=1;    M.at
(0, 0) = 1; M.at
(0, 1) = sin(alpha); M.at
(0, 2) = (1-cos(alpha))*center.x - sin(alpha)* center.y; M.at
(1, 0) = 0; M.at
(1, 1) = 1; M.at
(1, 2) = sin(alpha)* center.x +(1-cos(alpha))*center.y; M.at
(2, 0) = 0; M.at
(2, 1) = 0; M.at
(2, 2) = 1;

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透视变换(透视变换不保证平行性)

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Mat M=Mat::eye(3,3, CV_32FC1);    float alpha=0;    float tx=0;    float ty=0;    float scale=1;    M.at
(0, 0) = cos(alpha); M.at
(0, 1) = sin(alpha); M.at
(0, 2) =(1-cos(alpha))*center.x - sin(alpha)* center.y + tx; M.at
(1, 0) = -sin(alpha); M.at
(1, 1) = cos(alpha); M.at
(1, 2) =sin(alpha)* center.x +(1-cos(alpha))*center.y + ty; M.at
(2, 0) = 0.001; M.at
(2, 1) = 0.001; M.at
(2, 2) = 1;

复制代码

上述操作使用同一个opencv接口函数:warpPerspective(srcImg, dstImg, M, Size(width, height));

转载地址:http://albab.baihongyu.com/

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